A child and sled with a combined mass of 53.9 kg slide down a frictionless slope. If the sled starts from rest and has a speed of 5.71 m/s at the bottom, what is the height of the hill

1.66m

Explanation:

Using the conservation law

PE = KE

mgh = 1/2mv²

gh = V²/2

g is the acceleration due to gravity = 9.81m/s²

h is the height of the hill

V is the velocity = 5.71m/s

Substitute

9.81h = 5.71²/2

Cross multiply

2×9.81h = 5.71²

19.62h = 32.6041

h = 32.6041/19.62

h = 1.66m

Hence the height of the hill is 1.66m

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be