34. If R = 4.0 kΩ, C = 3.0 mF, ε = 15 V, Q = 12 mC, and I = 2.0 mA, what is the potential difference Vb − Va?

the potential difference Vb − Va = -3 V

Explanation:

The potential difference Vb − Va s given by

Vb − Va=  Capacitance / Charge + current x resistance - Electromotive force

Vb − Va=Q/C + I X R - E

V=Q / C=(12 x 10^-3) / (3 x 10^-3)

=0.012/0.003ss

=4V

alsoV=  1R = 2.0 x 10^-3 x 4 x 10^3

=0.002 X 4000

=8

Vb − Va= 4V + 8V- 15V

= -3V

Therefore, the potential difference Vb − Va = -3 V

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.