A ford escort of mass 600 kg collides with a Mack Truck of mass 24000 kg at rest. The Escort's incoming speed is 60 m/s and after the collision the remains of the Escort bounce straight back with a speed of 30 m/s (The paint of the truck's bumper is chipped.) If the collision lasts 2.0 seconds, approximately what is the average force of ythe truck on the car during this time

Because the dept in the ocean

This is the answer of your question

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j