A copper wire has a circular cross section with a radius of 1.00 mm. (a) If the wire carries a current of 2.50 A, find the drift speed of the electrons in the wire. (Assume the density of charge carriers (electrons) in a copper wire is n

Complete question is;

A copper wire has a circular cross section with a radius of 1.00 mm.

(a) If the wire carries a current of 2.5 A, find the drift speed of the electrons in the wire. (Assume the density of charge carriers (electrons) in a copper wire is; n_e = 8.46 × 10^(28) electrons/m³)

V_d = 5.88 × 10^(-5) m/s

Explanation:

We are given;

Radius; r = 1 mm = 0.001 m

Current; I = 2.5 A

Number of electrons per m³; n_e = 8.46 × 10^(28) electrons/m³

Now, formula for drift velocity is;

V_d = I/(A × n_e × q)

Where;

I is current

A is Area = πr² = π × 0.001²

A = 0.001²π

q is electron charge = 1.6 × 10^(-19) C

Thus;

V_d = 2.5/(0.001²π × 8.46 × 10^(28) × 1.6 × 10^(-19))

V_d = 2.5/42524.59815899144

V_d = 5.88 × 10^(-5) m/s

gets less

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: