The magnetic field at the center of a 0.60-cm-diameter loop is 2.7 mT . What is the current in the loop

12.898A

Explanation:

The formula for calculating the magnetic field in the loop bus expressed as;

B = Iμ0/2r

Given

Diameter d = 0.60cm

Radius r = d/2 = 0.30cm

r = 0.0030m

Permittivity of free space μ0 = 4π×10^-7

Magnetic field strength B = 2.7×10^-3T

Substitute into the formula and get I

2.7×10^-3 = 4π×10^-7I/2(0.0030)

2.7×10^-3 = 4π×10^-7I/0.0060

Cross multiply

2.7×10^-3 × 6.0×10^-3 = 4π×10^-7I

16.2×10^-6 = 4π×10^-7I

I = 16.2×10^-6/4π×10^-7

I = 16.2×10^-6/4(3.14)×10^-7

I = 16.2×10^-6/12.56×10^-7

I = 1.2898×10^{-6+7}

I = 1.2898×10

I = 12.898A

Hence the current in the loop is 12.898A

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