Starting from rest, a 94-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a magnitude of 750 N, and his speed at the bottom of the pole is 3.1 m/s. How far did he slide down the pole

Given that,

Mass of a firefighter, m = 94 kg

Frictional force, F = 750 N

Speed at the bottom of the pole is 3.1 m/s

It is required to find the distance he slide down the pole.

Using Work-energy theorem,

initial potential energy = final kinetic energy + work done

Solving for h, such that :

So, he will slide 2.63 m down the pole.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg