what is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its specific heat capacity is 0.96 J/gC. What is the temperature change?

1) The specific heat is the heat required to be added to a unit mass of the substance to cause a unit rise in its temperature

2) The temperature change is 20.92°C

Explanation:

The given parameters are;

The mass of the substance, m = 2.50 g

The heat released by the sample, ΔQ = 12 calories = 50.208 J

The specific heat capacity of the substance, c = 0.96 J/(g·°C)

Therefore, we have;

Heat released, ΔQ = Mass, m × Specific heat capacity, c × Temperature change, ΔT

Substituting in the known values gives

50.208 J = 2.50 g × 0.96 J/(g·°C) × ΔT

ΔT = 50.208 J/(2.5 g× 0.96 J/(g·°C)) = 20.92°C

The temperature change = 20.92°C

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)