You are moving a box across the floor with constant force of 50 N, the friction between the box and the floor is 20 N. After moving the box a distance of 10 m, what are: (a) net work done on the box. (b) your work done on the box. (c) work done by the friction? * 0 points

(a) net work done on the box 300 J

(b) your work done on the box 500 J

(c) work done by the friction 200 J

Explanation:

Given;

applied force on the box, f = 50 N

frictional force between the box and the floor, fk = 20 N

distance you moved box, d = 10 m

(b) Work done on the box as a result of the applied force;

W = F x d

W = 50 x 10 = 500 J

(c) Work done against the box by friction;

Wk = 20 x 10 = 200 J

(a) net work on the box;

∑W = W - Wk

∑W = 500 J - 200 J

∑W = 300 J

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.