A circuit is constructed with a 20-V power supply and two resistors in series: R1 = 4.0 ohms, and R2 = 2.0 ohms. What is the resulting current in the circuit?

The resulting current in the circuit is 3.33 A

Explanation:

Since we have two resistors R1 = 4.0 ohms and R2 = 2.0 ohms, since they are in series, their equivalent resistance R is R1 + R2 = 4 Ω + 2 Ω = 6 Ω.

Now, from Ohm's law we have that V = IR where V = voltage applied, I = current in the circuit and R = resistance.

Since it is given that we have a 20 V supply, V = 20 V and our equivalent resistance R =  6 Ω.

Making the current I subject of the4 formula, we have

I = V/R

substituting the values of V = 20 V and R =  6 Ω, we have

I = V/R

I = 20 V/ 6 Ω

I = 3.33 A

So, the resulting current in the circuit is 3.33 A

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