A swimmer can travel 2.30 m/s in still water. The swimmer heads directly west across a steam whose current is 1.20 m/s n. What is his velocity relative to the ground

velocity relative to the ground = 2.54 m/s

Explanation:

given data

still water Vx = 2.30 m/s

across a steam Vy = 1.20 m/s

solution

we get here first velocity relative to the ground is express as

velocity =      ...............1

put here value and we get

velocity  =

velocity = 2.54 m/s

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

c

explanation: