If an object is moving at 4 m/s in the x-direction, and 2 m/s in the y-direction, what is the velocity of the object written in terms of standard basis vectors?

V = 4i^ + 2j^

Explanation:

We are given;

Velocity in the x-direction; V_x = 4 m/s

Velocity in the y-direction; V_y = 2 m/s

Now, in terms of standard basis vectors, we normally write the resultant velocity as;

V = (V_x)i^ + (V_y)j^

Thus, the resultant velocity is;

V = 4i^ + 2j^

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over

where is the