A diagram of the forces being applied to a box is provided. If the net force acting on the box is 10N toward the right, what is the magnitude of force applied by the boy pulling to the left? Record your answer in the grid below. PLEASE HELP

14 N.

Explanation:

Let the force applied by the boy pulling to the left be x.

From the question given above, the following data were obtained:

Net force (Fₙ) = 10 N toward the right

Force applied by the boy pulling to the left = x

Next, we shall determine the total force in the left direction. This can be obtained as follow:

Force in the left direction (Fₗ) = x + 8

Next, we shall determine the total force in the right direction. This can be obtained as follow:

Force in the right direction (Fᵣ) = 11 + 21 = 32 N

Finally, we shall determine the force applied by the boy pulling to the left direction (i.e the value of x) as follow:

Net force (Fₙ) = 10 N toward the right

Force in the left direction (Fₗ) = x + 8

orce in the right direction (Fᵣ) = 32 N

Fₙ = Fᵣ – Fₗ (since the net force is toward the right direction)

10 = 32 – (x + 8)

Clear bracket

10 = 32 – x – 8

10 = 32 – 8 – x

10 = 24 – x

Collect like terms

10 – 24 = – x

–14 = –x

Divide both side by –1

x = –14/–1

x = 14 N

Thus, the force applied by the boy pulling to the left direction is 14 N.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.