A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.

-62.02πrads/sec^2

Explanation:

A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.

We need to convert to SI unit

9.549rev/ min= 1rad/sec

Then to convert angular speed of 3,550 rev/min to rad/sec

( 1 rad/sec)/9.549rev/min = x/5600rev/min

Then

(3,550 rev/min)/(9.549rev/min)= 371.77rad/sec

=118.4πrad/sec

6.823rad= 1rev

52.0 revolutions = 52×6.823= 354.796rads

= 113πrads

We will use expresion below to calculate our angular acceleration

w^2 - w^2(0)= 2α¢

Where w= angular speed

w(0)= initial angular

If final angular speed= 0

α=-w^2(0)/2¢

α=(-118.4π)^2/(2×113)

=-14018.56/226

-62.02πrads/sec^2

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.