If you throw a ball up with a velocity of 3 m/s , how long will it take for the ball to reach the top of its path

t = 0.306 s

Explanation:

Given that,

Initial velocity of the ball, u = 3 m/s

When it reaches the top of its path, its final velocity, v = 0

We need to find the time it takes the ball to reach the top of its path. It can be calculated using first equation of motion.

v = u +at

Here, a = -g

So, the ball will take 0.306 s to reach the top of its path.

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