the truck travels in a circular path having a radius of 50 m at a speed of v= 4 m/s for a short distance from s=0 its speed is increased by v = (0.05s) m/s2 . where s is in meters . determine its speed and the magnitude of its acceleration when it has moved s= 10m

2b2t

explanation:

2b2t

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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