a student releases a marble from the top of a ramp. the marble increases speed steadily and travels 120cm in 2.70s. what is the marbles final speed?

88.89 cm/s or 0.89 m/s.

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 cm/s

Distance travelled (s) = 120 cm

Time (t) = 2.7 s

Final velocity (v) =.?

The final velocity of the marble can be obtained as follow:

s = ½(v + u)t

120 = ½ × (v + 0) × 2.7

120 = (v + 0) × 1.35

120 = 1.35v + 0

120 = 1.35v

Divide both side by 1.35

v = 120/1.35

v = 88.89 cm/s

We may want to express the velocity in m/s. This can be obtained as follow:

100 cm/s = 1 m/s

Therefore,

88.89 cm/s = 88.89 cm/s × 1 m/s /100 cm/s

88.89 cm/s = 0.8889 m/s

88.89 cm/s = 0.89 m/s

Thus, the marble's final velocity is 88.89 cm/s or 0.89 m/s

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