If a 900N (downward) force is applied 2m away from the axis of rotation (to the right side) at an angle of 50 deg relative to the right horizontal, how much of that force contributes to the rotation of the system

Explanation:

We are expected to solve for the torque in this exercise

What is torque?

Torque is the force acting at a distance, it is calculated by multiplying force and distance. The SI units of torque are newton-meters, or N*m

the symbol is τ pronounced as tau

given a particular angle θ the torques is expressed as

τ = rFsin(θ)

given data

Force F= 900N

radius r= 2m

θ=50°

Substituting we have

τ = 2*900*sin50

τ = 1800sin50

τ =1800*0.766

τ =1378.8Nm

the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student