A horizontal spring with a 0.500 kg mass attached to one end, and the other end is secured to a wall. If the mass pulled 6.00 cm to the right of the equilibrium position, held constant for a moment, and released, what is the velocity of the mass when it is 4.00 cm to the left of the equilibrium position

To solve this question I had to search in google the spring constant = 375 N/m!

The velocity of the mass is 1.22 m/s.

Explanation:

To solve this question I had to search in google the spring constant = 375 N/m!

We can find the velocity of the mass by energy conservation:

Where:

m: is the mass = 0.500 kg

v: is the velocity of the mass=?

k: is the spring constant = 375 N/m (found in google)

and : are the initial and final position of the spring respectively

Therefore, the velocity of the mass is 1.22 m/s.

I hope it helps you!

v 154.9= 0.9 length length s little over 154.9cm

the area between the graph and the t axis