Pleaseee help
Will mark you as b.

d=m÷v

d=23÷10

d=2.3

v= m÷d

v=24÷12

v=2

m=d×v

m=23×5

m=115

d=53÷10

d=5.3

you have to draw the persons position over there

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.