A stone is thrown horizontally at a speed of 10 m/s from the top of a cliff 90.4 m high. How long does it take the stone to reach the bottom of the cliff?

The time it takes the stone to reach the bottom of the cliff is approximately  4.293 s

Explanation:

The given parameters are;

The height of the cliff, h = 90.4 m

The direction in which the stone is thrown = Horizontally

The speed of the stone in the horizontal direction = 10 m/s

The time, t, it takes the stone to reach the bottom of the cliff is given by the equation for free fall as follows;

h = 1/2 × g × t²

Where;

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values gives;

90.4 = 1/2 × 9.81 × t²

t² = 90.4/(1/2 × 9.81) ≈ 18.43 s²

t = √18.43 ≈ 4.293 s

The time it takes the stone to reach the bottom of the cliff is t ≈ 4.293 s.

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