A series RLC circuit has resistance R = Ω, inductive reactance XL = Ω, and capacitive reactance XC = Ω. If the maximum voltage across the resistor is ΔVR = V, find the maximum voltage across the inductor and the capacitor.

Explanation:

The question is incomplete. Here is the complete question.

A series RLC circuit has resistance R = 12Ω, inductive reactance XL = 30Ω, and capacitive reactance XC = 20Ω. If the maximum voltage across the resistor is ΔVR = 145V, find the maximum voltage across the inductor and the capacitor.

a) Voltage across the inductor is expressed as

VL = IXL

I is the current flowing in the inductor

XL is the inductive reactance

First we need to get I

According to ohms law, VR = IR

I = VR/R

I = 145/12

I = 12.08A

Since all the elements are in series, then the same current will flow in them.

Given XL = 30Ω

VL = 12.08(30)

VL = 362.5V

Hence the maximum voltage across the inductor is 362.5V

b) Voltage across the capacitor VC = IXC

Given

I = 12.08A

XC = 20Ω

VC = 12.08*20

VC = 241.67V

Hence the maximum voltage across the capacitor is 241.67V

3.2x10^7

c) up

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