A 15-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 29 N. Starting from rest, the sled attains a speed of 3.0 m/s in 8.8 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.

Explanation:

v² = u² + 2 a s

3² = 0 + 2 x a x 8.8

a = .511 m / s²

Let the frictional force acting on sled be F

F = m a

29 - F = 15 x .511

29 - F = 7.665

F = 21.335 N.

F = μ R , R = mg , μ is coefficient of kinetic friction.

F = μ x mg

μ = F / mg

= 21.335 / 15 x 9.8

= .145

coefficient of kinetic friction = .145

the answer is to check all of them! they all apply well at least i think so!

.) the observation by semmelweis that more mothers died of childbed fever when their doctors also worked in the morgue