A race car moving along a circular track has a centripetal acceleration of 15.4 m/s? If the car has a tangential speed of 30,0 m/s, what is the distance between the car and the center of the track?

r = 58.44 [m]

Explanation:

To solve this problem we must use the following equation that relates the centripetal acceleration with the tangential velocity and the radius of rotation.

a = v²/r

where:

a = centripetal acceleration = 15.4 [m/s²]

v = tangential speed = 30 [m/s]

r = radius or distance [m]

r = v²/a

r = 30²/15.4

r = 58.44 [m]

explanation:

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