Onur drops a basketball from a height of 10\,\text{m}10m10, start text, m, end text on Mars, where the acceleration due to gravity has a magnitude of 3.7\,\dfrac{\text{m}}{\text{s}^2}3. 7 s
2

m

3, point, 7, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. We want to know how many seconds the basketball is in the air before it hits the ground.
Which kinematic formula would be most useful to solve for the target unknown?
Assume the positive direction is upward and air resistance is negligible.
Choose 1
Choose 1

(Choice A)
A
v=v_0+atv=v
0

+atv, equals, v, start subscript, 0, end subscript, plus, a, t

(Choice B)
B
\Delta y = \left(\dfrac{v_0 + v}{2}\right)tΔy=(
2
v
0

+v

)tdelta, y, equals, left parenthesis, start fraction, v, start subscript, 0, end subscript, plus, v, divided by, 2, end fraction, right parenthesis, t

(Choice C, Checked)
C
\Delta y=v_0 t+\dfrac{1}{2}at^2Δy=v
0

t+
2
1

at
2
delta, y, equals, v, start subscript, 0, end subscript, t, plus, start fraction, 1, divided by, 2, end fraction, a, t, squared

(Choice D)
D
v^2=v_0^2+2a\Delta yv
2
=v
0
2

+2aΔy