2. A man in a hot air balloon drops his “five guy's hamburger” over the edge of the basket. The basket is 19 meters above the ground. How fast is the hamburger moving when it hits the ground?

19.3 m/s

Explanation:

Considering that no initial velocity was imparted to the hamburger, then we can use the distance covered formula for motion under constant acceleration (that of gravity) and solve for the time it took to reach the ground.

D = vi * t + (1/2) a * t^2

in our case

19 = 0 + 4.9 t^2

t^2 = 19/4.9

then t is approximately 1.97 seconds

We now use this time information in the equation for velocity under accelerated motion (due to gravity)

Vf = Vi + g * t

For our case:

Vf = 0 + 9.8 * 1.97 = 19.3 m/s

answer: good job it's all correct !

explanation: