A hot piece of brass (c = 380 J/kg˚C) is placed in water (c = 4180 J/kg˚C) to cool. The final temperature of the “mixture” will be closer to the initial temperature of which substance? Explain.

Given :

A hot piece of brass (c = 380 J/kg˚C) is placed in water (c = 4180 J/kg˚C) to cool.

To Find :

The final temperature of the “mixture” will be closer to the initial temperature of which substance.

Solution :

We know, change in temperature is inversely proportional to specific heat of the material.

In the given case specific heat of water is much greater than specific heat of brass.

So, change in temperature will be much in brass as compared to water.

Therefore, final temperature of mixture will be closer to the initial temperature of water.

Hence, this is the required solution.

specific latent heat of fusion, lf, of a substance is defined as the amount of heat required to change a unit mass of the substance from solid to liquid state, without any change in the temperature.

explanation: