If a single circular loop of wire carries a current of 63 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

The radius of the circular loop is 0.233 m

Explanation:

Given;

current on the circular loop, I = 63 A

magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T

The magnetic field at the center of a circular loop is given by;

Where;

R is the radius of the circular loop

μ is the permeability of free space = 4π x 10⁻⁷ T.m/A

Substitute the givens;

Therefore, the radius of the circular loop is 0.233 m

second mirror gathers light from a faraway object and reflects it to another mirror. - a.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.