Physics, 10.11.2020 14:00 portedon6626

Two protons are on either side of an electron as shown below: Diagram
The electron is 30 µm away from the proton on its left and 10 µm away from the proton on its right. What is the magnitude and direction of the net electric force acting on the electron? Note that
P=1.6×10(-19) c=-e

Select one:
a. 2.0×10−18N to the right
b. 7.0×10−24N to the right
c. 2.0×10−18N to the left
d. −9.59×10−24N to the right
e. 7.0×10−24N to the

Answers: 2

Show answers

Answers

Answer from: callieroberts1699

Choice a. approximately $2 \times 10^{-18}\; \rm N$ to the right.

Explanation:

Look up the Coulomb constant, :

$k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}$ .

Coulomb's Law may be used to find the magnitude of the electric force between the electron and each proton.

Let q_1 and q_2 denote the magnitude of electric charge on two point charges. Let denote the distance between these two charges.

By Coulomb's Law, the magnitude of the force between these two point charges would be:

$\displaystyle F = \frac{k\, q_1\, q_2}{r^2}$ .

The unit of distance in the Coulomb's constant here $k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}$ is meters. However, the distance between the electron and each proton is given in micrometers, $\rm \mu m$ . Note that $1\; \rm \mu m = 10^{-6}\; \rm m$ .

Convert these units to meters:

$30 \; \rm \mu m = 30 \times 10^{-6}\; \rm m$ .

$10 \; \rm \mu m = 10 \times 10^{-6}\; \rm m$ .

The question states that the magnitude of electric charge on each proton and each electron is $1.6\times 10^{-19}\; \rm C$ .

Using these information, find the magnitude of the electric force between the electron and each proton:

Between the electron and the proton on the left-hand side of the electron: $\begin{aligned}F &= \frac{k\, q_1\, q_2}{r^2}\\ &\approx \frac{\left(8.987552\times 10^{9}\; \rm N \cdot m^2\cdot C^{-2}\right) \times \left(1.6 \times 10^{-19}\; \rm C\right) \times \left(1.6 \times 10^{-19}\; \rm C\right)}{\left(30 \times 10^{-6}\; \rm m\right)} \\ &\approx 0.26 \times 10^{-18}\; \rm N\end{aligned}$ .Between the electron and the proton on the right-hand side of the electron: $\begin{aligned}F &= \frac{k\, q_1\, q_2}{r^2}\\ &\approx \frac{\left(8.987552\times 10^{9}\; \rm N \cdot m^2\cdot C^{-2}\right) \times \left(1.6 \times 10^{-19}\; \rm C\right) \times \left(1.6 \times 10^{-19}\; \rm C\right)}{\left(10 \times 10^{-6}\; \rm m\right)} \\ &\approx 2.56 \times 10^{-18}\; \rm N\end{aligned}$ .

The two protons in this question will both attract the electron. Therefore, the force between the electron and the proton on the left-hand side of the electron would point to the left. Similarly, the force between the electron the proton on the right-hand side of the electron would point to the right.

The magnitude of the net electric force on the electron would be:

$2.56 \times 10^{-18}\; \rm N - 0.26\times 10^{-18}\;\rm N \approx 2\times 10^{-18}\; \rm N$ .

These two forces act along the same line in opposite direction. Therefore, the resultant force of these two force would be in the direction of the larger force of the two.

In this question, the electric force between the electron and the proton on the right-hand side of the electron is larger. Hence, the net electric force of the protons on the electron should point to the right (towards the proton that is closer to the electron.)

Answer from: Quest

iron would move it is magnetic there is a mag field around the current in the wire

Answer from: Quest

the only real purpose of sputnik 1 was to beat the us into space. we were getting close to launching a useful satellite, explorer 1 - which launched on january 31, 1958. the ussr had to beat that, so they launched sputnik 1 on october 4, 19

Another question on Physics

Physics, 21.06.2019 20:20

Ateam of astronauts is on a mission to land on and explore a large asteroid. in addition to collecting samples and performing experiments, one of their tasks is to demonstrate the concept of the escape speed by throwing rocks straight up at various initial speeds. with what minimum initial speed vesc will the rocks need to be thrown in order for them never to "fall" back to the asteroid? assume that the asteroid is approximately spherical, with an average density p 3.84 x108 g/m3 and volume v 2.17 x 1012 m3 recall that the universal gravitational constant is g 6.67 x 10-11 n m2/kg2

Answers: 2

Answer

Physics, 21.06.2019 23:00

Atrain departs from its station at a constant acceleration of 5 m/s. what is the speed of the train at the end of 20s?

Answers: 1

Answer

Physics, 22.06.2019 08:00

What is a good example of instantaneous speed

Answers: 2

Answer

Physics, 22.06.2019 17:30

Atruck driver is attempting to deliver some furniture. first, he travels 8 km east, and then he turns around and travels 3 km west. finally, he turns again and travels 13 km to his destination. what is the drivers distance

Answers: 1

Answer

You know the right answer?

Two protons are on either side of an electron as shown below: Diagram
The electron is 30 µm a...

Questions