A dolphin propels itself through the water, increasing its speed from 5.0 m/s to 8.7 m/s in only 0.70 s. What is the magnitude of the dolphin's average acceleration during this time?

5.29 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 5.0 m/s

Final velocity (v) = 8.7 m/s

Time (t) = 0.70 s

Acceleration (a) =?

Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) /t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

Thus, with the above formula, we can obtain the acceleration of the dolphin as illustrated below:

Initial velocity (u) = 5.0 m/s

Final velocity (v) = 8.7 m/s

Time (t) = 0.70 s

Acceleration (a) =?

a = (v – u) /t

a = (8.7 – 5)/0.7

a = 3.7 / 0.7

a = 5.29 m/s²

Therefore, the dolphin's acceleration is 5.29 m/s².

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

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