Physics, 10.11.2020 17:00 organicmemez

If the same satellite orbited at the same velocity around a planet with three times the force of gravity, the orbit radius would be (multiplied, divided) by .

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Answer from: potato3999

the orbit radius would be divided by 3

Explanation:

In order to orbit the planet, the centripetal force of satellite must balance the gravitational force between planet and satellite.

centripetal Force = Gravitational Force

(Ms)(V)²/r = (G)(Ms)(Mₓ)/r²

V² = GMₓ/r

where,

V = velocity of satellite

G = Gravitational Constant

Mₓ = Mass of Planet

r = orbit radius

but, G = gr²/Mₓ

Therefore,

V² = (Mₓ/r)(gr²/Mₓ)

V = √gr equation (1)

where,

g = force of gravity

Now, for change in force of gravity:

V' = √g'r'

where,

g' = 3g

V' = V

Therefore,

V = √3gr' equation (2)

Comparing equation (1) and equation (2), we get:

√gr = √3gr'

gr = 3gr'

r = 3r'

r' = r/3

Hence, the orbit radius would be divided by 3.

Answer from: Quest

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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