A cliff diver running 3.60 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.00 s later. How high is the cliff and how far from the base of the cliff did the diver hit the water?
Help asap

The height of the cliff is 19.6m and the base of the cliff did the diver hit the water is 7.2m

The distance at the base of the cliff did that the diver hit the water is the horizontal distance. This is expressed as:

Given the following parameters

Speed v = 3.60m/s

Time t = 2.0s

Substitute into the formula to have:

The height of the cliff will be the vertical height derived according to the Newton's law of motion:

Hence the height of the cliff is 19.6m

Learn more here: link

Explanation:

It is given that,

The horizontal speed of a cliff diver,

It reaches the water below 2.00 s later, t = 2 s

Let is the distance where the diver hit the water. It can be calculated as follows :

Let is the height of the cliff. It can be calculated using second equation of motion as follows :

So, the cliff is 19.6 m high and it will hit the water at a distance of 19.6 m.

tube or goog with be a great resource to with that question

this could be newton#'s law of cooling. the cooling curve is exponential