What is the minimum speed with which he’d need to run off the edge of the cliff to make it safely to the far side of the river? the answer was 6 m/s the world-record time for the 100 m dash is approximately 10 s. given this, is it reasonable to expect brady to be able to run fast enough to achieve brady's leap?
a. yes, the obtained speed is less than the world-record.
b. yes, the obtained speed is almost equal to the world-record.
c. no, the obtained speed is greater than the world-record.
d. no, the obtained speed is almost equal to the world-record.

The answer is

A. Yes, the obtained speed is less than the world record

The explanation:

when the obtained speed is 6 m /s

and the world record speed = distance / time = 100 m / 10 s = 10 m/s

So, Yes, the obtained speed is less than the world record

Not only is it less, its also a reasonable average speed for a somewhat athletic person. Therefore, the leap is entirely possible.

-Samuel Brady gained his lasting notoriety for his leap over the Cuyahoga River around 1780 in what is now Kent, Ohio. After following a band of Indians into the Ohio country, a failed ambush attempt resulted in the band chasing Brady near the Cuyahoga River. To avoid capture, Brady leaped across a 22-foot (6.7 m) wide gorge of the river (which was widened considerably in the 1830s for construction of the Pennsylvania and Ohio Canal) and fled to a nearby lake where he hid in the water under a fallen tree using a reed for air.

answer is c

explanation:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day