An object is projected straight upward with an initial speed of 25.0 m/s. What's the maximum height obtained by the object ?

The maximum height obtained by the object is approximately 31.855 m

Explanation:

The vertical velocity of the object = 25.0 m/s

The height reached by the object, is given by the following formula;

v² = u²  -  2 × g × h

Where;

u = The initial velocity of the object = 25.0 m/s

v = The final speed of the object = 0 m/s at maximum height

h = The maximum height obtained by the object

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

0² = (25.0 m/s)²  -  2 × 9.81 m/s² × h

2 × 9.81 m/s² × h = (25.0 m/s)²

h = (25.0 m/s)²/(2 × 9.81 m/s²) ≈ 31.855 m

The maximum height obtained by the object, h ≈ 31.855 m.

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