Ron Burgandy's dog Baxter, is punted horizontally off a bridge by the bad man. Baxter's horizontal velocity is 20 m/s and the bridge is 20 m off the ground. If he lands safely 25 meters away
(because its a movie and not reality), how long was he in the air?

The actual time it takes to land from a height of 20 m is approximately 2.02 seconds

The time Baxter was in the air in the movie is 1.25 seconds

Explanation:

The given parameters are;

Baxter's horizontal velocity = 20 m/s

The height of the bridge off the ground = 20 m

The point where he lands (horizontally) = 25 m away

The time, t, Baxter was in the air is given by the following kinematic equation;

Horizontal velocity = (Horizontal distance)/(Time)

Substituting the known values gives;

20 = 25/t

∴ t  = 25/20 = 1.25

The time Baxter was in the air in the movie = t = 1.25 seconds

However from the equation for free fall, we have;

h = 1/2 × g × t²

∴ = √(h/(1/2 × g)) = √(20/(1/2 × 9.81)) ≈ 2.02 seconds

The actual time Baxter would be in the air ≈ 2.02 seconds.

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.