Physics, 12.11.2020 20:50 therronvictorjr
Un capacito de 2,00 μF esta conectado a una batería que tiene una diferencia de potencial de 12,00 V. Los alambres que estaban conectados a la batería se desconectan y se conectan a otro capacitor descargado. La diferencia de potencial en el capacitor de 2,00 μF es de 4,00 V. Calcular la capacitancia del segundo capacitor.
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Un capacito de 2,00 μF esta conectado a una batería que tiene una diferencia de potencial de 12,00 V...
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