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Physics, 12.11.2020 23:50 lalacada1

1. Calculate the specific heat capacity of the metal Use 4200 j/kg/°C for specific heat capacity of water
Heat gained by water = heat loss by the metal
M, XC X XT = M. XCX XT
M, X 4200 x 40-28 = 24.3 x cm x 99-40
M, X 4200 x 12 = 24.3 x x 59
M., 50,400 = 1.433.7C-I

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