An electron with a speed of 2.0 ´ 106 m/s moves into a uniform electric field of 500 N/C that is parallel to the electron’s motion. How long does it take to bring the electron to rest? (me = 9.11 ´ 10-31
kg, e = 1.6 ´ 10-19 C)
a. 2.3 ´ 10-8 s
b. 3.5 ´ 10-8 s
c. 1.2 ´ 10-7 s
d. 2.3 ´ 10-6 s

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.