A 5000 kg meteorite falls toward the earth. What is the magnitude of the earth's acceleration just before impact? The earth's mass is 5.98 × 10^24 kg.

The magnitude of the earth's acceleration is 8.20 × 10^27

The parameters given in the question are;

mass= 5000 kg

g= 9.81

earth's mass= 5.98 × 10∧ 24

The formula is

= mass × acceleration due to gravity/earth's mass

= 5000 × 9.81/ 5.98^24

= 49,050/5.98 × 10^24

= 8.20 × 10^27

Hence the magnitude of the earth's acceleration just before impact is 8.20 × 10^27

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8.193x10^-21m/s²

Explanation:

We have it that the gravitational force that is acting on this object is equal to the earth's gravitational force.

We start by using this formula

Ma = mg

We make a the subject of formula

a = mg/M

m = 5000kg

g = 9.8

M = 5.98x10^24kg

mg = 5000x9.8

= 49000

49000/5.98x10^24

= 8.193x10^-21m/s²

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explanation:

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