Obi Wan Kenobi is force pushing some bad guys into a forcefield. The bad guys (m= 300 kg) were originally at REST 5 meters away from the forcefield. It took them 0.5 seconds to hit the forcefield. How much force does Obi Wan apply?

F = 12000 N = 12 KN

Explanation:

First we need to find the acceleration of the bad boys by using second equation of motion:

s = Vi t + (1/2)at²

where,

s = distance covered = 5 m

Vi = Initial Velocity = 0 m/s

t = time taken = 0.5 s

a = acceleration = ?

Therefore,

5 m = (0 m/s)(0.5 s) + (1/2)a(0.5 s)²

a = 2(5 m)/(0.5 s)²

a = 40 m/s²

Now, we calculate the force applied by Newton's Second Law:

F = ma

where,

F = force = ?

m = mass of bad guys = 300 kg

Therefore,

F = (300 kg)(40 m/s²)

F = 12000 N = 12 KN

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards