A ball is thrown horizontally at 25.8m/s from 54 meter high cliff. How far from the base of the cliff does the ball land?

85.66m

Explanation:

Given the following data;

Horizontal velocity = 25.8m/s

Height = 54m

Initial velocity = 0

We would first of all, solve for the time taken using the formula for maximum height of a projectile.

H = ½gt²

Where;

We know that acceleration due to gravity is 9.8m/s²

Substituting into the equation

54 = ½*9.8t²

54 = 4.9t²

t² = 54/4.9

t² = 11.02

t = 3.32 secs

To find the distance;

Distance, x = velocity * time

x = vt

Substituting into the equation, we have;

x = 25.8*3.32

x = 85.66m

prndulum needs thread, weight clock to time swings