A basketball is shot with an initial velocity of 16 m/s at an angle of 55° to the horizontal. What is the approximate horizontal distance that the ball travels in
1.5 s?

approximately 13.77 m

Explanation:

We use the kinematic equations for the horizontal motion which is a uniform non-accelerated motion, and with initial velocity equal to 16 * cos(55). This is described by the equation:

then at t = 1.5 seconds, the covered distance becomes:

x = 9.177 * (1.5) = 13.7655  m

Round the answer to the number of decimals that the problem asks.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)