A 50-g ball moving at 10 m/s in the +x direction suddenly collides head-on with a stationary ball of mass 100 g. If the collision is perfectly elastic, what is the velocity of each ball immediately after the collision?A. +6.7 m/s, -3.3 m/sB. -6.7 m/s, +3.3 m/sC. +3.3 m/s, -6.7 m/sD. -3.3 m/s, +6.7 m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are the velocities

v is the final velocity

Given

m1 = 50g

u1 = 10m/s

m2 = 100g

u2 = 0m/s (stationary ball)

Required

Common velocity v

Substitute

50(10) + 100(0) = (50+100)v

500 = 150v

v = 500/150

v = 3.33m/s

Hence the velocity of each ball immediately after the collision is 3.33m/s

the components of a vector are the parts of the vectors that are to each other.

b perpendicular