Physics, 18.11.2020 16:50 alyssa337

You are driving down the road heading north at 15 m/s. An ambulance is driving in the opposite direction (south) towards you at 25 m/s. If the ambulance's siren emits sound at a frequency of 2 kHz, what frequency do you hear? Assume that the speed of sound is 340 m/s. a. 1780 Hz b. 1945 Hz c. 2254 Hz d. 2063 Hz e. 2000 Hz

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Answer from: kaoris6368

The frequency of the siren heard by the driver is approximately 2254Hz.

Hence, Option C) 2254Hz is the correct answer.

Given the data in the question;

Velocity of observer; v_o = 15m/s

Velocity of source; v_s = 25m/s

Actual frequency (source); f = 2kHz = 2000Hz

Velocity of sound; v = 340m/s

Frequency heard by observer; $f' = \ ?$

To find the frequency heard by the observer, we Doppler Effect Equation:

$f' = [ \frac{v+v_o}{v - v_s} ] f$

Where is the observed frequency, is the actual frequency, is the velocity of sound, v_o is the velocity of the observer and v_s is the velocity of the source.

We substitute our given values into the equation

$f' = [ \frac{340m/s\ +\ 15m/s}{340m/s\ -\ 25m/s} ] 2000Hz\\\\f' = [ \frac{355m/s}{315m/s} ] 2000Hz\\\\f' = 2253.968Hz\\\\f' = 2254Hz$

The frequency of the siren heard by the driver is approximately 2254Hz.

Hence, Option C) 2254Hz is the correct answer.

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Answer from: nataliatf5034

d. 2063 Hz

Explanation:

Given that the source of the sound (the ambulance) is heading towards the observer, we have;

fL= (v ± vL/v ± vS) fS

Where;

v = speed of sound = 340 m/s

vL = velocity of the listener = 15 m/s

vS = velocity of the source = 25 m/s

fS = frequency of source = 2 kHz

Since the source is moving towards the observer we subtract;

Substituting values;

fL = (340 - 15/340 - 25)2 *10^3

fL = 2063Hz

Answer from: Quest

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Answer from: Quest

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

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