A circular copper loop is placed perpendicular to a uniform magnetic field of 0.75 T. Due to external forces, the area of the loop decreases at a rate of 7.26 × 10^–3 m^2 /s. Determine the induced emf in the loop.

3.63×20^-3V

Explanation:

circular copper loop is placed perpendicular to a uniform magnetic field of 0.75 T. Due to external forces, the area of the loop decreases at a rate of 7.26 × 10^–3 m^2 /s. Determine the induced emf in the loop.

From Faraday-Newmann-Lenz law, the induced emf in the loop is given b

e=- Δθ/Δl

Δθ/Δl= rate of variation of the magnetic flux through the loop.

magnetic flux through the loop = BA

B = magnetic field

A i=area of the loop.

symbol: Φ

Since the magnetic field is constant, the variation of flux can be writing as

e=- B ΔA/Δt

=7.26 × 10^–3 m^2 /s × 0.5T

=3.63×20^-3V

5.4E-3 V

Explanation:

EMF = BA

EMF = (0.75)(7.26E-3)

EMF = 0.005445 V

EMF = 5.4E-3 V