Joyce pushes Efua, whose mass is 40.0 kg, with the force of 5.0 N. What is Efua's resulting acceleration?

Explanation:

Given that,

Mass of Efua, m = 40 kg

Force, F = 5 N

We need to find Efua's resulting acceleration. We know that the force acting on an object is given by :

F = ma

where a is acceleration

So, the resulting acceleration is .

d eras and periods

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg