A race car can be slowed with a constant acceleration of -11 m/s2. a. If the car is going 55 m/s, how many meters will it travel before it stops? b. How many meters will it take to stop a car going twice as fast?

137.5 meters

Explanation:

v = Vo + a t

so

v = 55 - 11 t

when is v = 0 ?

0 = 55 - 11 t

so t = 5 seconds to stop

d = Vo t + (1/2) a t^2

d = 55 (5) - (1/2) 11 (25)

= 275 - 137.5

=137.5 meters

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