A car is initially moving at 100 m/s and decides to gun it. They accelerate at a rate of 20 m/s/s for 10 seconds. How far did they travel during this time period?

dx = 2000 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

dx =  distance [m]

Vo = initial velocity = 100 [m/s]

a = acceleration = 20 [m/s²]

t = time = 10 [s]

dx = 100*10 + 0.5*20*10²

dx = 2000 [m]

Note: the positive sign in the above equation means that the car is increasing its velocity.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14