6. A sled traveling at a speed of 3.0 m/s slows to a stop 4.0 m from the point where its passenger rolled off. What is the magnitude of the horizontal net force that
slows the 110 N sled? (Assume ag = 10m/s2)
D

The magnitude of the horizontal net force acting on the sled is 12.375 N.

Given data:

The initial speed of sled is, u = 3.0 m/s.

The final speed of sled is, v = 0 m/s.

The distance covered before stopping is, s = 4.0 m.

The weight of sled is, W = 110 N.

Using the Newton's second law, the net horizontal force acting on the sled is given as,

F = ma

here,

m is the mass of sled.

a is the acceleration of sled.

Mass is calculated from the weight as,

W = mg

110 = m (10)

m = 11 kg.

Now, using the second kinematic equation of motion to obtain the acceleration of sled as,

Then the magnitude of net horizontal force is,

Thus, we can conclude that the magnitude of the horizontal net force is 12.375 N.

Learn more about the Newton's second law here:

link

-12.38 N

Explanation:

This question requires you to first find the acceleration then apply Newton's 2nd law of motion to find the force.

To find deceleration use the formula;

v²= u²+2ad ---where

v= final speed = 0 m/s

u= initial speed = 3.0 m/s

a= acceleration { in this case , deceleration} = ?

d= distance from the point where its passenger rolled off= 4.0 m

therefore ;

Mass of the sled is calculated from its weight force.

Weight force = mg

mass of sled = weight force / g  where g= 10 m/s²

mass of sled = 110/10 = 11kg

The magnitude of horizontal net force will be : F= ma  where ;

m= mass of sled = 11 kg

a= deceleration = -9/8 m/s²

F = 11 * -9/8 = -12.38 N

Force is acting on the opposite direction of the initial motion of the sled.

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.