How much of the total energy in Problem 3 and 4 has been transformed to kinetic energy?

I am only a HS Freshman so I might be wrong

3. Its potential energy and the formula for PE = mgh so you would use the weight given (Weight = mg) and mg is in the (Potential Energy) forumula so we multiply 3 by 30 and get 90 Joules

4. We would do the same thing with this: PE = mgh; PE = 10*3 = 30 Joules

Once again I am only a Freshman and I have taken Private AP Physics classes so just maybe wait for someone who is more confident.

This is just what I would answer

btw, for problem 5, the fromula for kinetic energy is 1/2*m*v^2

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

could you add the photo?

explanation: