A block of mass m kg = 2 is pulled by a force F = 40 N upwards through a height h m = 2 . Find the work done on the block by the applied force

F and its weight mg. ( g = 10m/s^2)

Explanation:

Weight mg = (2) (10) = 20 N

Work done by the applied force

WF = Fh cos0°

As the angle between force and displacement is 0°

or WF = (40) (2) (1) = 80 J

Similarly, work done by its weight

Wmg = (mg) (h)cos 180°

or Wmg = (20)(2)(-1) = - 40 J

-TheUnknownScientist

explanation:

newton's third law, for every action there is an equal and opposite reaction.

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